MATHEMATICS II

and the detreminant of this matrix is

The other matrices we use in the Cramer’s rule are

and their determinats are

Then the solution is

as follows:

Then

Now we add the equations to eliminate the term

then one gets

If we back-subsitute

into the equations

we obtain

Then these lines intersect at the point

the inverse of

one has

then

is obtained.  Since

is given, we  should have

From this equation one has

Then answer is  

The other matrices we use in the Cramer’s rule are

The determinant of these matrices are

Hence the solution of this system of linear equations is

the point

must also provide both  of the equations. Hence we obtain

Then one gets

we obtain

Hence

and the determinant of

is 6.

Hence the system of linear equations above can now be expressed as a single matrix equation

that is

we multiply both sides of the equation by

on the left, getting

is the identity

The matrix equation above implies that

is a matrix of type of

and

is a matrix of type of

 then the type of the product matrix

If we solve this equation we get

Therefore the

correct answer is A.